![]() ![]() ![]() The reel is a solid disk, free to rotate in a vertical plane about the horizontal axis passing through its center. Do the values agree? Describe what specific effects might produce a systematic error in your result. 1 mldavis086 10 0 Homework Statement An object with a mass of m 5.10 kg is attached to the free end of a light string wrapped around a reel of radius R 0.250 m and mass M 3.00 kg. Example calculation h 240 mm, w 120 mm Strong axis: I y 1 12 h 3 w 1 12 ( 240 m m) 3 120 m m 1. Compare your calculated disk mass to that using the large scale at the front of the room. Moment of inertia Rectangular shape/section (formula) Strong Axis I y 1 12 h 3 w Weak Axis I z 1 12 h 3 w Dimensions of rectangular Cross-section.(4ed) 10.4 A flywheel in the shape of a solid cylinder of radius R 0.60 m. The procedure is to divide the complex shape into its sub shapes and then use the centroidal moment of inertia formulas from Subsection 10.3.2, along with the parallel axis theorem (10.3.1) to calculate the moments of inertia of parts, and finally combine them to find the moment of inertia of the original shape. Propagate the uncertainty in your measurements to your result. Using energy methods, calculate the moment of inertia of the can if it takes.for all the point masses that make up the object. Explain your calculation of the disk mass step-by-step, and give the results leading to your answer. We defined the moment of inertia I of an object to be.From the applied torque, disk radius, and angular acceleration, calculate the disk mass. This interactive shows a composite shape shape consisting of a large rectangle with a smaller rectangle subtracted.From the radius of the axle pulley, calculate the torque acting upon the spinning disk.From the initial height and time it takes to reach the ground, determine the acceleration, and thus the tension force in the string. Wrap the string of the hanging mass around the axle pulley of the disk on the Rotational Motion Apparatus and drape the string over the pulley clamped to the table edge.The angular acceleration of the pulley can be calculated directly from the downward acceleration of the mass, and also predicted from the rotational form of Newton’s second law. In this experiment, the only torque acting on the pulley is the tension force at radius r from the mass as it is pulled down by gravity. In the same way, torque, defined as \vecMR^2 ![]() Angular acceleration \alpha, for example, is simply linear acceleration a divided by the radius r of circular motion. Equipment: Rotary motion sensor and rotational accessory. Rotational kinematic quantities have many analogies to linear ones. For an extended, massive object, the rotational inertia is more complicated to calculate theoretically. ![]()
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